BIOL 1398 Lecture Notes - Lecture 2: Gamete, Phenotype, Heredity

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aquamarinepanda121

1 Apr 2019

School

University of Houston

Department

Biology

Course

BIOL 1398

Professor

Thijs

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Document Summary

14. 1 mendel used the scientific approach to identify two laws of inheritance. Cross pollinating purple flowered plants with white flowered plants: this experiment allowed him to deduce 2 fundamental principles of heredity. In mendel"s experiment of cross breeding the f1 generation was entirely purple flowered, but in the f2 some white flowered plants reappeared, although the majority was still purple. True breeding: heterozygous = an organism that has two different alleles for a gene. Not true- breeding: phenotype = an organism"s appearance/ observable traits, genotype = genetic make up, ex. Pp and pp have the same phenotype (purple flowers) but different: the testcross genotypes, breeding an organism of unknown genotype with a recessive homozygote to reveal the genotype of the organism, ex. Purple flower is unknown if it is pp or pp, so we cross t with pp, if the resulting offspring is all purple then we know its pp.

Related Questions

A violet-flowered, long-stemmed hybrid pea plant was crossed with a true-breeding white-flowered, short-stemmed pea plant with the following offspring: 47 violet, long-stemmed plants, 40 white, long-stemmed plants, 38 violet, short-stemmed plants, 41 white, short-stemmed plants. If two of the white, long-stemmed plants above were crossed you would expect to get which of the results listed below?

a. all white, long-stemmed

b. 1/2 white, short-stemmed; 1/2 white, long-stemmed

c. 3/4 white, long-stemmed; 1/4 white, short-stemmed

d. 9/16 violet, long-stemmed plants, 3/16 white, long-stemmed plants, 3/16 violet, short-stemmed plants, 1/16 white, short-stemmed plants

e. They do not all have the same genotype so the expected progeny can not be determined.

QUESTION 3 In a given experiment, a chi-square value of 2 is obtained with 3 degrees of freedom. Using a p value of 0.05, should you reject or fail to reject the null hypothesis?

a. reject.

b. fail to reject.

c. depends on the experimental data

QUESTION 4 A researcher planted 120 seeds from an F2 cross of two hybrid purple flowered plants and got 85 purple flowered progeny and 35 white flowered progeny. What was the Chi- Square value for this result?

yellowlouse759

1. A true breeding tall pea line is crossed with atrue breeding short line. The F1 plants are all short. The F1 arecrossed with themselves to produce an F2. If the difference (tallvs. short) is due to a single locus, what proportion of the F2individuals do you expect to be tall?

2. Imagine that a researcher crossed the peas in theexample above, and counted 100 F2. 86 were short. 14 were tall. Doa chisquare test to see whether the results conform to a singlelocus cross with the allele coding for short plants dominant to theallele coding for tall plants.

3. A clematis from a true-breeding line with whiteflowers and short corollas (line A) is crossed to a clematis from atrue-breeding line with deep red flowers and long corollas (lineB). The resulting offspring, the F1, are all pink-flowered, withcorollas of medium length. An individual from the F1 iscrossed to an individual from line A. The resulting F2 offspringare as follows: 25% white flowers and short corollas, 25% whiteflowers with medium corollas, 25% pink flowers with short corollas,25% pink flowers with medium corollas.
What is the most likely genetic mechanism determining flower colorand corolla length? If a plant from the F1 listed above were selfed(crossed with itself), what proportion of the F2 offspring wouldyou expect to be white flowered with short corollas?

4. A man and a woman walk into a genetic counselorâsoffice. They have just had a child diagnosed with situs inversus, acomplete transposition of the internal organs from left to right,and vice versus. This condition usually produces no obvioussymptoms. It is caused by an autosomal recessive allele. What isthe chance that their next child will have the same condition? Whatmight this suggest about the parents?
Another man and woman walk into the same office. The father is anachondroplasic dwarf. The mother is of normal stature. (Look upachondroplasia, it is a lethal dominant). What is the chance thattheir first child will be a dwarf?

Please show work! (:

carminebeaver663

BIOL 1398 Lecture Notes - Lecture 2: Gamete, Phenotype, Heredity

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