PHYS 211 Lecture 16: Unit 16 Parallel Axis Theorem and Torque.pdf

43 views2 pages
17 Jun 2015
Department
Course
Professor

Document Summary

Prove theorem relating moments of inertia about parallel axis. Develop the equation that determines the dynamics for rotational motion. Find the rotational analog of mass that is the moment of inertia. For a solid object, the only motion relative to the center of mass is rotation. The moment of inertia about a chosen axis if the moment of inertia through a parallel axis that goes through center of mass is known. So the center of mass rotating about the axis plus the rod itself rotating at the same rate. Moment of inertia about dumbbell is sum of the moment of inertia around the rod and both bells. Inertia sphere about given axis = 2/5mr^2 + m(l/2)^2. If dw/dt > 0, then alpha points in same direction of omega. If dw/dt < 0, then alpha points in opposite direction of omega. Does not depend on choice of coordinate system. Everything is a property of the object itself.

Get access

Grade+20% off
$8 USD/m$10 USD/m
Billed $96 USD annually
Grade+
Homework Help
Study Guides
Textbook Solutions
Class Notes
Textbook Notes
Booster Class
40 Verified Answers
Class+
$8 USD/m
Billed $96 USD annually
Class+
Homework Help
Study Guides
Textbook Solutions
Class Notes
Textbook Notes
Booster Class
30 Verified Answers

Related textbook solutions

Related Documents

Related Questions