CHEN 3005 Lecture Notes - Lecture 16: Opata Language, Pandit
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Unsteady heat transfer all solutions = for slabs, look in book for cylinders and spheres. T(x) x direction----------> assuming it"s symmetriclooks same on both sides. Boundary conditions symmetry could have conditions for right and left of solid, or can just know that at middle, derivative = 0. @ x = b (edge of solid) h describes heat transfer mechanisms taking place inside of the liquid we think the normal is pointing out so we think it should be in positive x direction. How to check sign of boundary conditionsdraw out what you know and see what sign makes sense. Assume solid is hot and liquid is cool. Draw out t profile cools a bit slower @ solid the negative sign on left means t derivative is less than 0. This problem is difficult to solve b/c inhomogeneous bc which involves t and derivative of t.