MATH 126 Lecture Notes - Lecture 19: Alternating Series Test, Alternating Series, Direct Comparison Test

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13 Mar 2015
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Math 126: calculus ii - lecture 19: summary of 8. 1-8. 4 (convergence tests) Test for divergence: if lim n an 0 doesn" t exist , no conclusion). then n=1. Integral test, comparison test : only for series with positive terms. )bn+1 bn ii. lim n bn=0 seriesis convergent n=1. An is convergent, then an & root test: n an+1 lim n convergent, it is convergent. ) An is convergent. (if a series is absolutely lim n n an i. l<1, an is convergent. ii. l>1 d. n. e. ,anis divergent. iii. l=1, thereis noconclusion. Bn with positive terms, an bn for all i. if . Bn is divergent. n n n n n. If an lim n bn converge or both series diverge. =c wherecis a finite number>0, then either both series. 0 bn+1 bn ,f (x)= x x3+2 (1 /2) (x3+2 (3/2) x3) 1 (3/2)x3 f "(x )= x3+2 x3+2 (1 /2) f " (x)= .

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