MATH 019 Lecture Notes - Lecture 11: Adze

• School: University of Vermont
• Department: Mathematics
• Course: MATH 019
• Professor: Krisan Geary

Document Summary

2=25 that are not in the form y = an expression in terms of. , we learn to take the derivative of equations that are not explicitly functions of. X . since y function is still determined of. X and we by x can we say it is an implicit write it as. 2=25 t y find y at the point. Cx ) as y step a : take the derivative w/ respect. A to x of both sides of the equation. [ ycx ) ] adz ( 25 ] Steps : replace ycx ) with y step. Steps : evaluate @ c 3,4 ) y. X2[ ycx ) ]3 - xatycx ) d find y y. 2 +3 cycx ) 32g " cx ) ) = 2 divide by more to the ztcxt 335% everything numerator y. Cl of the tangent line to ( x - y. 3 ( x - ycx) - 1) 2.