CET 3464 Lecture Notes - Lecture 9: Cavitation, Inequation, Reynolds Number
23 Jan 2021
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Answer::- we can apply - energy equation between surface of the reservoir and pump inlet. Now "turbine the (tot) p. +2, th pump + p2 + x2v2 + Z th turbine g 29 89 29 since there is no turbine in the system, and there in between point o and . &2 = 1. 052 1. substitute vi-o, p = palm and x = 1. he, total now so) patm 2,0 + 29 + p2 89 ( + overy + z + he, total pg 29. P2 se k 29 where p2 19 the patm " equation- p9 g -(22-2,)-he, total pz = pump inlet pressure ure head. calculate the available net positive. Re svd m for water at 25 c : f = 997. 0 kg/m3 kg/mos pv = 3. 169 kpa & patm = 101. 3 kpa y= 8. 91x104 so, re = 997. 0 x 1. 474 x.
