University College - Chemistry Chem 112A Lecture Notes - Lecture 13: Sodium Chloride, Lead

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0. 1m ki -> k+, i- in 1l of solution. Ksp = 1. 4 x 10-8 = s(0. 1 + 2s)2. I- is present in solution initially, which pushes the reaction left and there is less dissolution of. The presence of a common ion will result in a decrease of the solubility of the salt. But ag2cro4 is not soluble so first k2cro4 must be dissolved. Then agno3 is added creates ag2cro4 precipitate. Nacl added, so there is an excess of cl- ions. Original reaction pushed to the right, disrupting the equilibrium, and pulling the. Ag+ ions out of solution with cl- ions. The less soluble species is pulled out of solution, and forces the slightly non soluble species to dissolve. 0. 015m agno2 + 0. 005m pbno2 + nacl -> agcl + pbcl2. Agcl is insoluble (ksp = 1. 6 x 10-10) Pbcl2 is slightly soluble (ksp = 1. 6 x 10-5) If q = [pb2+][cl-]2 > ksp = 1. 6 x 10-5.

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