MATH 10B Lecture Notes - Riemann Sum
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The velocity of a car t seconds after applying the breaks is given by v(t) = 88 - 1st ( ft / see) . How far does the car travel while breaking ? p (t) - position of car t seconds after braking. " ( t) (cid:8869) pct) is an anti derivative of vct) / (f) dt =/ ( 88 - 1st ") at. + c (cid:8869) pct) = 88t - is t% to for some c. distance while breaking p( 891s) - pco) = (88. 9%-3-1%-1) + c) - c. Find the area under sin (x) between = 0 and. + i sin (5) + e- (e) + (e) + sin( )+ sin(%-) (5) (1+53) Idea : write large sums more compactly in general: =m ai = am + anti + + an , where ai are terms (numbers) depending on the index i. 1 : = , if = 12 + 22 + 3 c- =/ i --2, =3.
