MA 35100 Lecture Notes - Lecture 25: California State Route 1, Computer-Aided Technologies, If And Only If

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23 Nov 2022
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An nxn matrix a is invertible iff there is an uxh matrix (such that. Ac = ca =1( we call can inverse for al. Theorem 3. 9: a is nonsingular iff a is invertible. If a is uxn has a left inverse, i. e. 3 with ca=i, or a right inverse, i. e. d with ad =1, then we can show a is non-singular. Cax= cb, x =cb: x = cb is the unique. A (db):ad (b):b: c. x= db is a solution to. If a is invertible, ac= ca:i (and c =a " as a is nonsingular - Turns out that a" is the only (with cac=ca:i). If you have found either a left inverse car right inverse pfor a, you have found a " 3 satisfies a -sa+131:0 r now a is invertible. Useful, but only when you have a lot of into about a. I3 we can manipulate to solve for the us through rr, referencing matrix multiplication.

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