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10 Nov 2019
The height of a ball thrown upward with an initial velocity of 48 ft/sec from a height of 14 ft above the ground can be represented by s=â16t2+48t+14, where t is the number of seconds after the ball is thrown. How many seconds will it take the ball to reach the ground? Round your answer to two decimal places.
The height of a ball thrown upward with an initial velocity of 48 ft/sec from a height of 14 ft above the ground can be represented by s=â16t2+48t+14, where t is the number of seconds after the ball is thrown. How many seconds will it take the ball to reach the ground? Round your answer to two decimal places.
proffarah45Lv1
12 Jan 2023
Collen VonLv2
15 Feb 2019
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