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12 Nov 2019
The solution of ODE: [t^2 D^2 + 2tD]y(t) = 0 is: a)y = A + B/t b)A + Bt)At + Bt^2 d) Alnt + B/t
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Bunny Greenfelder
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10 Mar 2019
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Consider the polynomials p_1 = t^2 +2t + 1, p_2 = t^2 +2 in P_2. Determine the relation between the constants a, b, c in order for the vector u at^2 +bt +c to be a member of the Span {p_1, p_2}
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Suppose that A, B, C, D, and E are matrices with the following sizes: Determine whether the given matrix expression is defined. For those that are defined, give the size of the resulting matrix. EA BT(A + ET) (CT + D)BT (BDT)CT
We can put the ODE: [D(D^2 + tD)]y(t) in the form: a) [D(D^2 + tD)]y'(t) b) [D(D^2 + tD)D]y(t) c) [D^3 + tD^2 + D]y(t) d) [D^3 + tD^2]y(t)
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