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13 Nov 2019
Simple logarithims- Which is correct for expressing in terms of logx, logy? ![](https://prealliance-textbook-qa.oneclass.com/qa_images/homework_help/question/qa_images/24/2417917.png)
Simple logarithms- Which is correct for expressing in terms of log x, log y? log squareroot x^2/5y^2 = log squareroot x^2 - log squareroot 5y^2 = log squareroot x^2 - log squareroot 5 + log squareroot y^2 therefore log x + log y - log squareroot 5 OR log (x^2/5y^2)^1/2 = 1/2 log (x^2/5y^2) = 1/2 (log x^2 - log 5y^2) = 1/2 (2 log x - (log 5 + log y^2)) = 1/2 (2 log x - log 5 - 2 log y)
Simple logarithims- Which is correct for expressing in terms of logx, logy?
Simple logarithms- Which is correct for expressing in terms of log x, log y? log squareroot x^2/5y^2 = log squareroot x^2 - log squareroot 5y^2 = log squareroot x^2 - log squareroot 5 + log squareroot y^2 therefore log x + log y - log squareroot 5 OR log (x^2/5y^2)^1/2 = 1/2 log (x^2/5y^2) = 1/2 (log x^2 - log 5y^2) = 1/2 (2 log x - (log 5 + log y^2)) = 1/2 (2 log x - log 5 - 2 log y)
Sixta KovacekLv2
6 Apr 2019