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13 Nov 2019
Given: f(x) = x^2 + 6x + 5 Find the x value of the vertex (turning point). X = -3 None of the above x = -2 x = 3 Using the same function as in #1, find the y value of the vertex. None of the above y = -4 y = 32 y = 4 Is this vertex you found above a minimum point or a maximum point? Maximum point Minimum point What is the y-intercept of the function in #1? (5, 0) None of the above (0, 5) (0, 6) What are the zeros of the parabola in #1? (that is, at what point does the graph cross the x-axis?) {(1, 0), (5, 0)} None of the above {(-1, 0), (-5, 0)} {(0, -1), (0, -5)}
Given: f(x) = x^2 + 6x + 5 Find the x value of the vertex (turning point). X = -3 None of the above x = -2 x = 3 Using the same function as in #1, find the y value of the vertex. None of the above y = -4 y = 32 y = 4 Is this vertex you found above a minimum point or a maximum point? Maximum point Minimum point What is the y-intercept of the function in #1? (5, 0) None of the above (0, 5) (0, 6) What are the zeros of the parabola in #1? (that is, at what point does the graph cross the x-axis?) {(1, 0), (5, 0)} None of the above {(-1, 0), (-5, 0)} {(0, -1), (0, -5)}
Jarrod RobelLv2
28 May 2019