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10 Nov 2019
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Use a double integral to calculate the volume of the 3D-region which is under z = x + 2y and above the region in the first quadrant of the xy-plane that is enclosed by the curves y = 2x. and y = x2.
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Related questions
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Use a double integral to calculate the volume of the 3D-region in the 1st octant which is under the plane z = 60x + 12y and above the bounded region of the xy-plane that is enclosed by the curves x = y2, and x = 2y.
2. Double integral over a region), polar coordinate a. Let f(x, y) 3x2 xy y3 y, and a region RE 1, 1] by [-1, 1] for (x, y) find b. Find the volume under the surface z x, y Vi-xa and above the triangular region formed by y J x, x 1, and the x-axis c. Find the volume defined by z x, y 4 -x2 y2 above the circular region bounded by the two axes and the circle x2 y2 4 in the first quadrant (hint: use polar coordinate system for the circular region)
Red text is the Answer, would just like steps to solve.
(a) The area of the region in the plane lying inside the circle s 4, above the line y 1, and to the right of y =-z. (b) The double integral JJ 2ry dA, where R is the region in the first quadrant enclosed by 2,y V, and 1-0.
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