1
answer
0
watching
303
views
10 Nov 2019
Vector Functions
A circular cylinder of radius 1 and the hyperbolic paraboloid z = x2 - y2 intersect as shown in Which vector function r(t) = x(t)i + y(t)j + z(t)k has the curve of intersection as its graph if x(0) = 1? r(t) = (cos t)i + (sin t)j + (cos 2t + 1)k r (t) = (cos t)i + (sin t)j + (cos 2t)k r (t) = (sin t)i + (cos t)j + (cos 2t + 1)k r(t) = (sin t)i + (cos t)j + (cos 2t)k r (t) = (sin t)i + (cos t)j + (cos 2t - 1)k r (t) = (cos t)i + (sin t)j + (cos 2t - 1)k
Vector Functions
A circular cylinder of radius 1 and the hyperbolic paraboloid z = x2 - y2 intersect as shown in Which vector function r(t) = x(t)i + y(t)j + z(t)k has the curve of intersection as its graph if x(0) = 1? r(t) = (cos t)i + (sin t)j + (cos 2t + 1)k r (t) = (cos t)i + (sin t)j + (cos 2t)k r (t) = (sin t)i + (cos t)j + (cos 2t + 1)k r(t) = (sin t)i + (cos t)j + (cos 2t)k r (t) = (sin t)i + (cos t)j + (cos 2t - 1)k r (t) = (cos t)i + (sin t)j + (cos 2t - 1)k
Read by 1 person
mvp-do-brazilLv10
2 Oct 2022