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Solve the differential equation(x^2 + xy + 3y^2)dx - (x^2 + 2xy)dy = 0:
Differential equation
1.exact (4x-2xy-y^2)dx-(x+2)^2dy=0
2.homogeneous (2x-y)dx-(x+4y)dy=0
3. linear 2y(y^2-x)dy=dx
Thank you very much
Solve the Bernoulli equation: dy/dx -2xy =2xy^2
A. y = 1/Ce^-x^2 -1 B. y = - Ce^x^2/2 C. y = - e^-x^2 +C D. y = 1/C-e^-x2