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13 Nov 2019
f(x) =-2x2 +8 Let f be the function given by (x)2x+8 as shown above. The graph of f crosses the y-axis at P(o.8) and the a-axis at point Q(2,0) #1) write an equation for the line passing through points P and Q. (slope intercept form) #2) write an equation for the tangent to the graph of f at point Q. (slope intercept form) #3) Find the x-coordinate of the point on the graph of f between point P and Q, at which the line tangent To the graph of fis parallel to the line PQ.
f(x) =-2x2 +8 Let f be the function given by (x)2x+8 as shown above. The graph of f crosses the y-axis at P(o.8) and the a-axis at point Q(2,0) #1) write an equation for the line passing through points P and Q. (slope intercept form) #2) write an equation for the tangent to the graph of f at point Q. (slope intercept form) #3) Find the x-coordinate of the point on the graph of f between point P and Q, at which the line tangent To the graph of fis parallel to the line PQ.
Keith LeannonLv2
2 Nov 2019