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13 Nov 2019

Write down the iterated integral which expresses the surface area ofz=y7cos3xz=y7cos3⁡x over the triangle with vertices (−1,1),(1,1),(0,2)(−1,1),(1,1),(0,2):

∫ba∫g(y)f(y)h(x,y)−−−−−−√dxdy∫ab∫f(y)g(y)h(x,y)dxdy


a=a=

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b=b=

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f(y)=f(y)=

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g(y)=g(y)=

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h(x,y)=h(x,y)=

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Lelia Lubowitz
Lelia LubowitzLv2
1 Feb 2019

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