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13 Nov 2019
* the total are enclosed answer is correct (the first one). However the second one is NOT (9-pi*r)/2 (1 pt) A wire of length 18 is cut into two pieces which are then bent into the shape of a circle of radius and a square of side s. Then the total area enclosed by the circle and square is the following function of s and r pi(r 2)+s12 If we solve for s in terms of r, we can reexpress this area as the followin function of r alone: (9-pir)/2 Thus we find that to obtain maximal area we should let r To obtain minimal area we should let 7, . Note: You con onn
* the total are enclosed answer is correct (the first one). However the second one is NOT
(9-pi*r)/2
(1 pt) A wire of length 18 is cut into two pieces which are then bent into the shape of a circle of radius and a square of side s. Then the total area enclosed by the circle and square is the following function of s and r pi(r 2)+s12 If we solve for s in terms of r, we can reexpress this area as the followin function of r alone: (9-pir)/2 Thus we find that to obtain maximal area we should let r To obtain minimal area we should let 7, . Note: You con onn
Reid WolffLv2
2 Oct 2019