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13 Nov 2019
Remember when we computed integrals before, we said that we could use any anti- derivative and we would always get the same answer. a. Find J(3x-x2)dix b. Use the anti-derivative used in part a to compute . 3x-x-2)dx. Do this 3 times: first by ignoring the "4 C" (ie., letting C = 0), once by letting C = 5 . And finally by keeping +C in the expression as an arbitrary constant. Why does the value of the constant in the indefinite integral not affect the value of the definite integral? c.
Remember when we computed integrals before, we said that we could use any anti- derivative and we would always get the same answer. a. Find J(3x-x2)dix b. Use the anti-derivative used in part a to compute . 3x-x-2)dx. Do this 3 times: first by ignoring the "4 C" (ie., letting C = 0), once by letting C = 5 . And finally by keeping +C in the expression as an arbitrary constant. Why does the value of the constant in the indefinite integral not affect the value of the definite integral? c.
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Beverley SmithLv2
6 Jul 2019