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13 Nov 2019
Answer on. Screen wrong 1 pt) Use the Laplace transform to solve the following initial value problem y',-4y' + 23y = 0 y(0) = 2, y'(0) = 3 irst using Y for the Laplace transform of y(t), i eãY-E(y(t) } ind the equation you get by taking the Laplace transform of the differential equation Y-4Y =0 Now solve for Y(s)-(2s-5)/(s^24s+25) By completing the square in the denominator and inverting the transform find y(t)= e^(2t)(2cos(sqrt(190-sin(sqrt(190
Answer on. Screen wrong
1 pt) Use the Laplace transform to solve the following initial value problem y',-4y' + 23y = 0 y(0) = 2, y'(0) = 3 irst using Y for the Laplace transform of y(t), i eãY-E(y(t) } ind the equation you get by taking the Laplace transform of the differential equation Y-4Y =0 Now solve for Y(s)-(2s-5)/(s^24s+25) By completing the square in the denominator and inverting the transform find y(t)= e^(2t)(2cos(sqrt(190-sin(sqrt(190
Trinidad TremblayLv2
12 Jan 2019