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watching
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13 Nov 2019
(1 point) The series (4n +3)2 n=1 is convergent. (A). According to the Remainder Estimate for the Integral Test, the error in the approximation s Sn (where s is the value of the infinite sum and Sn is the n-th partial sum) is 12 (B). Find the smallest value of n such that this upper bound is less than 0.0001
(1 point) The series (4n +3)2 n=1 is convergent. (A). According to the Remainder Estimate for the Integral Test, the error in the approximation s Sn (where s is the value of the infinite sum and Sn is the n-th partial sum) is 12 (B). Find the smallest value of n such that this upper bound is less than 0.0001
Nelly StrackeLv2
23 Apr 2019