Pricing
Log in
Sign up
Home
Homework Help
Study Guides
Class Notes
Textbook Notes
Textbook Solutions
Booster Classes
Blog
Calculus
1
answer
0
watching
54
views
13 Nov 2019
Find a set of parametric equations of the line that passes through the point (-1,4,-2) and is parallel to v = 3i-ij (x(t), y(t), Z(t))-(L=-Itat, y-4-6r,:-21Ã )
For unlimited access to Homework Help, a
Homework+
subscription is required.
You have
0
free answers left.
Get unlimited access to
3.8 million
step-by-step answers.
Get unlimited access
Already have an account?
Log in
Deanna Hettinger
Lv2
13 Nov 2019
Unlock all answers
Get
1
free homework help answer.
Unlock
Already have an account?
Log in
Ask a question
Related textbook solutions
Calculus
4 Edition,
Rogawski
ISBN: 9781319050733
Single Variable Calculus: Early Transcendentals
4th Edition, 2018
Stewart
ISBN: 9781337687805
CALCULUS:EARLY TRANSCENDENTALS
4 Edition,
Rogawski
ISBN: 9781319050740
Related questions
Find a set of parametric equations of the line that passes through the poin (-1, 4, -2) and is parallel to v 3i - 6j. (x(t), y(t), z(t))-C x=-1 + 3t, y 4-61,2-2 | Submit Answer Save Progress
6. Find a set of parametric equations for the line: (a) Line passes thorugh the points (0,0) and (4,-7). (b) Line passes through the points (1,4) and (5,-2). 7. Given a parametric equations: x = t2, y-3-4Vt, find and y 8. Convert the following polar coordinates (r,0) to the rectangular coordinates (z, y): (a) For the point (r,0) = (8 ). (b) For the point (r;0) = (-2,,). (c) For the point (r,0) = (V3,
#1
#2
Find parametric equations and symmetric equations for the line. (Use the parameter t.) The line through (1, 2, 0) and perpendicular to both i + j and j + k (x(t), y(t), z(t)) = ( ) The symmetric equations are given by -(x - 1) = y - 2 = z. x + 1 = -(y + 2), z = 0. x - 1 = y - 2 = -z. x + 1 = -(y + 2) = z. x - 1 = -(y - 2) = z. Find symmetric equations for the line that passes through the point (3, -5, 7) and is parallel to the vector -1, 2, -4 -(x + 3) = 2(y - 5) = -4(z + 7). -(x - 3) = 2(y + 5) = -4(z - 7). x - 3/-1 = y + 5/2 = z - 7/-4. x + 3/-1 = y - 5/2 = z + 7/-4. x + 3 = y + 5/2 = z - 7/-4. Find the points in which the required line in part (a) intersects the coordinate planes. point of intersection with xy-plane point of intersection with yz-plane point of intersection with xz-plane Find parametric equations and symmetric equations for the line. (Use the parameter t.) The line through (1, 2, 0) and perpendicular to both i + j and j + k (x(t), y(t), z(t)) = The symmetric equations are given by -(x - 1) = y - 2 = z. x + 1 = -(y + 2), z = 0. x - 1 = y - 2 = -z. x + 1 = -(y + 2) = z. x - 1 = -(y - 2) = z.
Show transcribed image text
Find parametric equations and symmetric equations for the line. (Use the parameter t.) The line through (1, 2, 0) and perpendicular to both i + j and j + k (x(t), y(t), z(t)) = ( ) The symmetric equations are given by -(x - 1) = y - 2 = z. x + 1 = -(y + 2), z = 0. x - 1 = y - 2 = -z. x + 1 = -(y + 2) = z. x - 1 = -(y - 2) = z. Find symmetric equations for the line that passes through the point (3, -5, 7) and is parallel to the vector -1, 2, -4 -(x + 3) = 2(y - 5) = -4(z + 7). -(x - 3) = 2(y + 5) = -4(z - 7). x - 3/-1 = y + 5/2 = z - 7/-4. x + 3/-1 = y - 5/2 = z + 7/-4. x + 3 = y + 5/2 = z - 7/-4. Find the points in which the required line in part (a) intersects the coordinate planes. point of intersection with xy-plane point of intersection with yz-plane point of intersection with xz-plane Find parametric equations and symmetric equations for the line. (Use the parameter t.) The line through (1, 2, 0) and perpendicular to both i + j and j + k (x(t), y(t), z(t)) = The symmetric equations are given by -(x - 1) = y - 2 = z. x + 1 = -(y + 2), z = 0. x - 1 = y - 2 = -z. x + 1 = -(y + 2) = z. x - 1 = -(y - 2) = z.
cyanmoose493
Weekly leaderboard
Home
Homework Help
3,900,000
Calculus
630,000
Start filling in the gaps now
Log in
New to OneClass?
Sign up
Back to top