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13 Nov 2019
PROBLEM 1 Show that if f(x) is a function only of x, then u = f(x) sin (ay + b) is a solution of the partial differential equation (a and b are constants) 2u provided that f(x) satisfies the ordinary differential equation Hence show that is a solution of the partial differential equation, where A and B are arbitrary constants,
PROBLEM 1 Show that if f(x) is a function only of x, then u = f(x) sin (ay + b) is a solution of the partial differential equation (a and b are constants) 2u provided that f(x) satisfies the ordinary differential equation Hence show that is a solution of the partial differential equation, where A and B are arbitrary constants,
Trinidad TremblayLv2
23 May 2019