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13 Nov 2019
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1. The series Σ np is called p-series. Show that the Ratio Test cannot be used to determine the convergence or divergence of the series. (The p-series converges if p > 1 and diverges if 0 p 1.)
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Irving Heathcote
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Does the series converge absolutely, converge conditionally, or diverge? Choose the correct answer below. The series converges absolutely since the corresponding series of absolute values is the p-series with p > 1. The series converges conditionally per the ratio test. The series converges conditionally per the alternating series test. The series diverges per the nth-term test. The series converges absolutely since the corresponding series of absolute values is geometric with |r|
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Does the series converge absolutely, converge conditionally, or diverge? Choose the correct answer below. The series converges absolutely since the corresponding series of absolute values is the p-series with p > 1. The series converges conditionally per the ratio test. The series converges conditionally per the alternating series test. The series diverges per the nth-term test. The series converges absolutely since the corresponding series of absolute values is geometric with |r|
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viridiancaribou56
Hi, Can you please help me solve this question using clear detailed steps?
(Please mention all the letters that apply in the end) thanks :)
3-sin n (1 point) This series converges Check all of the following that are true for the series Σ A. This series converges OB. This series diverges C. The integral test can be used to determine convergence of this series. D. The comparison test can be used to determine convergence of this series. E. The limit comparison test can be used to determine convergence of this series F. The ratio test can be used to determine convergence of this series G. The alternating series test can be used to determine convergence of this series.
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