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watching
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13 Nov 2019
4. Analogous as we did it in question 2, use implicit differentiation to prove that de [arccos(z)] =-ãã¼ arccos(2) | 1-x Hint. You will need the following precalculus fact, namely that whenever A is a real number for which arccos(A) is defined, then sin (arccos(A)) = V
4. Analogous as we did it in question 2, use implicit differentiation to prove that de [arccos(z)] =-ãã¼ arccos(2) | 1-x Hint. You will need the following precalculus fact, namely that whenever A is a real number for which arccos(A) is defined, then sin (arccos(A)) = V
Nelly StrackeLv2
30 Oct 2019