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13 Nov 2019
6. -10.37 points WebAssignCalcLT2 17.1.002f Notes Ask Your Teacher Find the solution of the second-order linear differential equation that satisfies the given initial conditions. y"+2y' + 2y = 0 y(0) = 0 y'(0) =-4 y(x) -/0.37 points WebAssignCalcLT2 17.3001 a My Notes Ask Your Teacher A mass of 4 kg is attached to the end of a spring with a natural length 0.6 m. A force of 32 N is required to maintain the spring stretched to the length of 0.8 m in the positive x direction beyond the equilibrium point at x0. It is stretched to a length of 0.8 m and then released with initial velocity 0. Find the position x(t) of the mass at any time t. x(t) = 8. /0.41 points WebAssignCalcLT2 17.3.001g My Notes Ask Your Teacher A mass of 1 kg is attached to the end of a spring immersed in a fluid with damping constant c = 2. To stretch the spring 2 m beyond its equilibrium position, it takes a force of 10 N. External vibrations create a force represented by F(t)17 sin(2t). The spring is compressed in the negative x direction x(0)2 m from its equilibrium with zero initial velocity. Find the equation for the position of the mass at any time t. x(t) = Activate Windows Go to Settings to activate Windows
6. -10.37 points WebAssignCalcLT2 17.1.002f Notes Ask Your Teacher Find the solution of the second-order linear differential equation that satisfies the given initial conditions. y"+2y' + 2y = 0 y(0) = 0 y'(0) =-4 y(x) -/0.37 points WebAssignCalcLT2 17.3001 a My Notes Ask Your Teacher A mass of 4 kg is attached to the end of a spring with a natural length 0.6 m. A force of 32 N is required to maintain the spring stretched to the length of 0.8 m in the positive x direction beyond the equilibrium point at x0. It is stretched to a length of 0.8 m and then released with initial velocity 0. Find the position x(t) of the mass at any time t. x(t) = 8. /0.41 points WebAssignCalcLT2 17.3.001g My Notes Ask Your Teacher A mass of 1 kg is attached to the end of a spring immersed in a fluid with damping constant c = 2. To stretch the spring 2 m beyond its equilibrium position, it takes a force of 10 N. External vibrations create a force represented by F(t)17 sin(2t). The spring is compressed in the negative x direction x(0)2 m from its equilibrium with zero initial velocity. Find the equation for the position of the mass at any time t. x(t) = Activate Windows Go to Settings to activate Windows
Trinidad TremblayLv2
29 Sep 2019