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First cost of equipment = $6,000 Salvage value after 5 years = $1,500 MACRS depreciation is used as a 5-year property. Income-tax rate for the company = 34% Capital gains are taxed at 15% rate. Year BTCF, $ 0 -6,000 (Initial cost) 1 1,600 2 1,600 3 1,600 4 1,600

5 1,600 6 1,600 9,000 ( Market value) Reference: Ref 12-2 The tax on depreciation recapture in year 6 is equal to __________________.

A. $3,060

B. $6,000

C. $2,040

D. $9,000

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Chika Ilonah
Chika IlonahLv10
28 Sep 2019

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Related questions

First cost of equipment = $200,000

Market value at the end of year 6 = $10,000

MACRS depreciation is used. The equipment is 5-year property.

Incremental income-tax rate for the company = 35%

Year

0

1

2

3

4

5

6

BT-CF in $

-200K

60K

63K

66K

69K

72K

75K

Market value = 10K

The first-year after tax-cash flow is equal to _____________.

suppose the asset bought for $100,000 has been sold for $100000 after two years. which of the following statement is most accurate?

I- there is capital gain

II- there is capital loss

III- there is depreciation recapture

2- Suppose the asset has been sold for $110,000 after two years. Initial purchase price of $100,000, a gross income of $40,000, a current book value of $60,000, a depreciation amount of $10,000, and tax rate of 50%. What is the taxable income?

3- A truck was purchased 3 years ago for $45,000 and can be sold today for $24,000. The operating costs are $9,000 per year, and it is expected to last 4 more years with a $5,000 salvage value. A new truck, which will perform that same service, can be purchased for $50,000, and it will have a life of 10 years with operating costs of $28,000 per year and a $10,000 salvage value. What is the value that should be used as P for the presently owned vehicle in a replacement study?

4- an asset was acquired by Hugo and Sons for a first cost of $100000 via a 10% per year loan that needs to be paid back using equal uniform amounts at the end of each year in 2 years. The amount of interest paid for the first year on this loan is?

5- an asset was acquired by Hugo and Sons for a first cost of $100000 via a 10% per year loan that needs to be paid back using equal uniform amounts at the end of each year in 2 years. In the first year, the company claimed $60,000 depreciation. If the gross income is $200,000 and operating expenses are $50,000, then the taxable income is?

  1. 1. What is the capitalized value of an infinite series of $1,000 biennial (every two years) payments? MARR = 10%

    $4,950

    $4,025
    .

    $4,350


    $4,762

    1. 2. Frank West Enterpises would like to choose one of the following plans for expansion. Using present worth analysis, find the best alternative among the three alternatives and the Do-Nothing.

      Alt. A

      Alt. B

      Alt. C

      Initial Cost

      $10,000

      $21,000

      $8,000

      EUAB

      $6,000

      $7,000

      $4,000

      EUAC

      $1,500

      $1,000

      $2,000

      Salvage Value

      $2,000

      $8,000

      $3,000

      Life

      2 Years

      3 Years

      2 Years

      Use a MARR of 10%.

      .

      Do-Nothing
      .

      Alt. C
      .

      Alt. B
      .

      Alt. A

      3.

      1. U. S. Engineering is investigating the possibility of acquiring new automated packaging equipment at a cost of $12,000. It is expected that the equipment will have a salvage value of $1,000 at the end of its useful life of 10 years. It is determined by the plant engineering department at the company that the operation and maintenance cost will be $500 in the first year and will gradually increase every year starting year 2 at the rate of $50 until the equipment is retired. Determine the equivalent uniform annual cost (EUAC) if MARR for the company is 10%.

        $2,575.95


        $2,150.50
        .

        $2,176.60
        .

        $2,184.40

        4.

        1. The cash flows given in table below are for two different alternatives. MARR =10%

          Data

          C

          D

          Initial Cost

          $20,000

          $80,000

          Uniform Annual Benefits

          $6,000

          $10,000

          Salvage Value

          $5,000

          $20,000

          Useful Life in years

          5

          infinity

          The equivalent uniform annual worth (EUAW) of alternative N is ______________.

          Hint: Assume the Salvage Value is never realized since N is infinite.

          $2,000

          $1,920

          $1,762


          $2,476

          5.

          1. Compare the following plans using a MARR of 6%.

            Data

            Plan X

            Plan Y

            Equipment First Cost

            $50,000

            $75,000

            Annual Operation & Maintenance Cost

            $3,000

            $2,500

            Salvage Value

            $10,000

            $0

            Service Life, Years)

            25

            50


            $6,728; $7,255


            $7,255; $9,000
            .

            $6,728; $7,728
            .

            $6,728; $8,200

            6.

            1. LAEP, Inc. wants to evaluate two methods of shipping their products. The following cash flows are associated with each alternative:

              Data

              Method

              A

              B

              Life (Years)

              10

              10

              First Cost

              $700,000

              $1,512,000

              M&O Cost

              $18,000

              $9,000

              M&O Cost Gradient

              $900

              $775

              Annual Benefit

              $154,000

              $303,000

              Salvage Value

              $142,000

              $210,000

              Annual profits are based on amount of products which can ordinarily be shipped each year as a function of the amount of vehicles or service purchased with the first cost and the M&O costs.

              Using a MARR of 15%, calculate the equivalent uniform annual cash flow (EUAB - EUAC) for each alternative.

              Determine the most desirable alternative based on the results.

              $389.57, $445.90; Method A


              $445.90, $389.57; Method A
              .

              $445.90, $389.57; Method B
              .

              $389.57, $445.90; Method B
            7.

            1. For the cash flow diagram shown, which of the following equations properly calculates the uniform equivalent (A)?

              n

              0

              3

              6

              9

              12

              15

              Dollars

              $100

              $100

              $100

              $100

              $100

              $100


              A=100(A/P,i,15)+ 100(A/F,i,3)


              A=100(A/P,i,15)


              A=100(A/F,i,3) + 100(A/F,i,15)


              A=100(A/P,i,3) + 100(A/F,i,3)
              8.

              1. Three different alternatives shown in table below are being considered by U. S. Engineering systems.

                Assume that alternatives X and Z are replaced at the end of their lives.

                Data

                Alternative X

                Alternative Y

                Alternative Z

                Initial Cost

                $6,000

                $1,000

                $1,500

                Uniform Annual Benefits

                $810

                $125

                $ 230

                Useful Life in Years

                20

                infinite

                10

                MARR

                12%

                The NPW for alternative

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