An investment in manufacturing equipment yields the followingcash flows for 8 years. At the end of the 8th year the equipmentcan be sold for $15,000. Assuming an interest rate of 14%(compounded annually), how much would you be willing to invest inthis manufacturing equipment?
C=? I=2000 I=2000 I=2000 I=2000 I=1000 I=1000 I=1000 I=1000 L=$15,000 0 1 2 3 4 5 6 7 8
C: Cost, I: Income,L: Salvage Value
An investment in manufacturing equipment yields the followingcash flows for 8 years. At the end of the 8th year the equipmentcan be sold for $15,000. Assuming an interest rate of 14%(compounded annually), how much would you be willing to invest inthis manufacturing equipment?
C=? | I=2000 | I=2000 | I=2000 | I=2000 | I=1000 | I=1000 | I=1000 | I=1000 | L=$15,000 |
0 | 1 | 2 | 3 | 4 | 5 | 6 | 7 | 8 |
C: Cost, I: Income,L: Salvage Value
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Related questions
1.) An investment inmanufacturing equipment yields the following cash flows for 8years. At the end of the 8th year the equipment can be sold for$15,000. Assuming an interest rate of 14% (compounded annually),how much would you be willing to invest in this manufacturingequipment?
C=? | I=2000 | I=2000 | I=2000 | I=2000 | I=1000 | I=1000 | I=1000 | I=1000 | L=$15,000 |
0 | 1 | 2 | 3 | 4 | 5 | 6 | 7 | 8 |
C:Cost, I: Income, L: SalvageValue
2.) Suppose that thenominal annual interest rate on an investment is 12%. Calculate theeffective interest rate if compounding occurs continuously.
3.)
Assume $50,000 is paidfor an asset in present time that yields annual cash flow of $6,000dollars per year in Years 1 through 10, as shown in the tablebelow. At the end of Year 10 the salvage value of the asset is$40,000. Calculate the rate of return on this investment. (In otherwords, find the value of the interest rate i that makesthe Net Present Value of the investment equal to zero - this isalso called the Internal Rate of Return.)
A hint here is thatyou will need to solve this problem either by trial and error orusing the IRR function in Excel.
C=-$50,000 | I=$6000 | I=$6000 | I=$6000 | ... | I=$6000 | L=$40,000 |
0 | 1 | 2 | 3 | ... | 10 |