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17 Nov 2019
Solve the differntial equation subject to the initial conditions.
Solve the differntial equation subject to the initial conditions. x dy/dx + y = cos x; x > 0; x = pi when y = 1
Solve the differntial equation subject to the initial conditions.
Solve the differntial equation subject to the initial conditions. x dy/dx + y = cos x; x > 0; x = pi when y = 1
26 Jul 2023
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Irving HeathcoteLv2
5 Nov 2019
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