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Find the Fourier Series of f (x) = 8 sin 6x on the interval [- pi, pi]. f(x) = 48 / k sin kx f(x) = 14 / k cos kx f(x) = 48 / k cos kx + 48 / k sin kx f(x) 8 sin 6x (the function is already periodic)

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30 May 2023

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Lelia LubowitzLv2

10 Jun 2019

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