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27 Nov 2019
A uniform electric field has a magnitude 2.30 kV/m and points inthe +x direction.
(a) What is the electric potentialdifferencebetween x = 0.00 m plane and the x =4.20 m plane? kV
(b) A point particle that has a charge of +2.90 µC is released fromrest at the origin.What is the change in the electric potentialenergy of the particleas it travels from the x = 0.00 mplane to the x= 4.20 m plane?
mJ
(c) What is the kinetic energy of the particle when it arrivesatthe x = 4.20 m plane?
mJ
(d) Find the expression for the electric potential V(x)ifits value is chosen to be zero at x = 0. (Usethefollowing variables as necessary: x.)
V(x) = Enter amathematical expression.kV
A uniform electric field has a magnitude 2.30 kV/m and points inthe +x direction.
(a) What is the electric potentialdifferencebetween x = 0.00 m plane and the x =4.20 m plane? kV
(b) A point particle that has a charge of +2.90 µC is released fromrest at the origin.What is the change in the electric potentialenergy of the particleas it travels from the x = 0.00 mplane to the x= 4.20 m plane?
(b) A point particle that has a charge of +2.90 µC is released fromrest at the origin.What is the change in the electric potentialenergy of the particleas it travels from the x = 0.00 mplane to the x= 4.20 m plane?
mJ
(c) What is the kinetic energy of the particle when it arrivesatthe x = 4.20 m plane?
mJ
(d) Find the expression for the electric potential V(x)ifits value is chosen to be zero at x = 0. (Usethefollowing variables as necessary: x.)
V(x) =
(c) What is the kinetic energy of the particle when it arrivesatthe x = 4.20 m plane?
mJ
(d) Find the expression for the electric potential V(x)ifits value is chosen to be zero at x = 0. (Usethefollowing variables as necessary: x.)
V(x) =
Enter amathematical expression.
kV
maalsahil2Lv2
11 Feb 2023
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