Question

A local juice manufacturer distributes juice in bottles labeled 32 ounces. A government agency thinks that the company is cheating its customers. The agency selects 25 of these bottles, measures their contents, and obtains a sample mean of 31.7 ounces with a standard deviation of 0.70 ounce. Use a 5% significance level to test the agency's claim that the company is cheating its customers. The appropriate null hypothesis for this situation is: HO: = 31.7 O H0: H = 32 HO: u = 31.7 OHO: x = 32 The appropriate alternative hypothesis for this situation is: Ha: p > 31.7 Ha: X < 32 Ha: > 32 Ha: u < 32 Ha: X < 31.7 Ha: > 31.7 O Ha: u < 31.7 Ha: u > 32 The value of the statistic for this test is = 49) (round answers to three places after the decimal.) and the p-value is 49) (round answers to three places after the decimal.) There - enough statistical evidence, at the 5% level, that the company is cheating its customers.