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10 Nov 2019
Reduce each to the following parts of equations to a single equations in one variable by addition or subtraction of equations then solve for x and y. 3x+6y =- 15 5x-3y = 1 -13y/13=24/13y=1.85 2x - 3y = - 1 x-2=-2 x-2y-2 2(2y-2)-3y=-1 3x=-by-15 x=-2y-5 (5x-2y-5)=1 -10y-25-3y=-1 4y-4-3y=-1 y-4=-1 y=3 5x-3(1-35)=1 5x-5.6=1 1 5x/5=6.6/5 Lambda=1.32 x=1.32 y=1.55 x=4 y=3 x-2(3)=-2 x-6=-2 x=4 On the graph provided draw pairs of lines representing the pairs of equations given in previous exercise 17(your choice a or b), and verify your solution. The following problems have a scientific context You do need to understand all the details, but you should be able to rearrange each of the given equations algebraically as directed. The location of the " " X. of a molecule consisting of two of masses m1 and m2 is given by (m1+m2)X = m x + m2x2 where x and the position of the atoms x1 and x2 are measured from some common Origin find m1 in terms of the other quantities.
Reduce each to the following parts of equations to a single equations in one variable by addition or subtraction of equations then solve for x and y. 3x+6y =- 15 5x-3y = 1 -13y/13=24/13y=1.85 2x - 3y = - 1 x-2=-2 x-2y-2 2(2y-2)-3y=-1 3x=-by-15 x=-2y-5 (5x-2y-5)=1 -10y-25-3y=-1 4y-4-3y=-1 y-4=-1 y=3 5x-3(1-35)=1 5x-5.6=1 1 5x/5=6.6/5 Lambda=1.32 x=1.32 y=1.55 x=4 y=3 x-2(3)=-2 x-6=-2 x=4 On the graph provided draw pairs of lines representing the pairs of equations given in previous exercise 17(your choice a or b), and verify your solution. The following problems have a scientific context You do need to understand all the details, but you should be able to rearrange each of the given equations algebraically as directed. The location of the " " X. of a molecule consisting of two of masses m1 and m2 is given by (m1+m2)X = m x + m2x2 where x and the position of the atoms x1 and x2 are measured from some common Origin find m1 in terms of the other quantities.
Deanna HettingerLv2
13 Sep 2019