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Particle A is fixed in place at x = -0.300 m on the x axis and particle B, with a mass of 3 kg, is fixed in place at the origin. Particle C (not shown) can be moved along the x axis, between particle B and x = 8. Figure 13-36b shows the x component Fnet,x of the net gravitational force on particle B due to particles A and C, as a function of position x of particle C. The plot actually extends to the right, approaching an asymptote of -4.12 × 10-10 N as x ? 8. What are the masses of (a) particle A and (b) particle C?

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Jamar Ferry
Jamar FerryLv2
26 May 2019

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Related textbook solutions

Physics: Principles with Applications
7th Edition, 2013
Giancoli
ISBN: 9780321625922

Related questions

Figure 21-33(a) shows charged particles 1 and 2 that are fixed inplace on an x axis. Particle 1 has a charge with a magnitude of|q1| = 19.0e. Particle 3 of charge q3 = +15.0e is initially on thex axis near particle 2.Then particle 3 is gradually moved in thepositive direction of the x axis. As a result, the magnitude of thenet electrostatic force on particle 2 due to particles 1 and 3changes. Figure 21-33(b) gives the x component of that net force asa function of the position x of particle 3. The scale of the x axisis set by xs = 1.40 m. The plot has an asymptote of F2,net = 2.543× 10-25 N as x ? 8. As a multiple of e and including the sign, whatis the charge q2 of particle 2?

Figure 21-29(a) shows an arrangement of three charged particles.Particles A and C are fixed on the x axis, but particle B can bemoved along a circle centered on particle A. During the movement, aradial line between A and B makes an angle θ relative to thepositive direction of the x axis (figure 21-29(b)). The curves infigure (c) below give, for two situations, the magnitude Fnet ofthe net electrostatic force on particle A due to the otherparticles. That net force is given as a function of angle θ and asa multiple of a basic amount F0. For example on curve 1, at θ =180o, we see that Fnet = 2F0. (a) For the situation correspondingto curve 1, what is the ratio of the charge of particle C to thatof particle B (including sign)? (b) For the situation correspondingto curve 2, what is that ratio?

Part A Curve 1: In the solution provided to this question F0=force of particle B on particle A and F is the force of particle Con particle A. We are given that Fnet=2F0 at θ=180*

How do we know that 2F0= F0-F? (Doesn't this meanthat F0=2Fo+F which doesn't make sense?)

Part B Curve 2: it is clear that the ratio ofFmax/Fmin = 1.25/0.75 What comes after that..the solution says:

5/3= (1+(1/4) qA/qC) / (1-(1/4)qA/qC)

what is the next step to simplify this and get a solution..?


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