Consider aseries RL circuit with R= 84.0 ⦠and an unknown inductor L, drivenby an AC emf with Erms= 33.0 Volts at frequency f= 6.80kHz. If we measure the current in the circuit, we findIrms= 0.167 Amps.
What is theinductance L?
What is themagnitude of the phase angle between the applied voltage and thecurrent?
What is theratio of the power dissipated in the resistor to the power thatwould be dissipated if the inductor were not in the circuit?(Assume that Erms stays the same.)
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A circuit is constructed with anAC generator, a resistor, capacitor and inductor as shown. Thegenerator voltage varies in time as ε =Va - Vb = εmsinÏt, where εm= 24 V and Ï = 141 radians/second. At this frequency,the circuit isin resonance with the maximum value of the current Imax = 0.81 A.The capacitance C = 140μF. The values for the resistance R and theinductance L are unknown.1)What is L, the value of the inductance of the circuit?mH2)What is Umax,C, the value of the maximum energy stored in thecapacitor during one cycle?J3)What is ÎU, the total energy dissipated in the circuit in onecycle?J4)What is Q, the quality factor of this ciruit?5)What is R, the value of the resistance of the circuit?Ω6)Suppose now the value of the capacitance in the circuit is doubled(Câ = 2C) and the inductance is changed appropriately to keep thecircuit in resonance at angular frequency Ï = 141 radians/s whilethe generator voltage and resistance are kept constant. How does Q,the quality factor of the circuit, change, if at all?Q increasesQ decreasesQ stays the same
