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12 Nov 2019

A 0.500 kg pendulum bob passes through the lowest part of its pathat a speed of 3.40 m/s.
(a) What is the tension in the pendulum cable at this point if thependulum is 80.0 cm long? (in Newtons)
(b) When the pendulum reaches its highest point, what angle doesthe cable make with the vertical? (in Degrees)
(c) What is the tension in the pendulum cable when the pendulumreaches its highest point? (in Newtons)

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Jarrod Robel
Jarrod RobelLv2
12 Nov 2019

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Related textbook solutions

Physics: Principles with Applications
7th Edition, 2013
Giancoli
ISBN: 9780321625922

Related questions

The length of a simple pendulum is 0.86 m and the mass of the particle (the "bob") at the end of the cable is 0.25 kg. The pendulum is pulled away from its equilibrium position by an angle of 8.55° and released from rest. Assume that friction can be neglected and that the resulting oscillatory motion is simple harmonic motion.


(a) What is the angular frequency of the motion? rad/s

(b) Using the position of the bob at its lowest point as the reference level, determine the total mechanical energy of the pendulum as it swings back and forth. J

(c) What is the bob's speed as it passes through the lowest point of the swing? m/s

The length of a simple pendulum is 0.86 m and the mass of theparticle (the "bob") at the end of the cable is 0.25 kg. Thependulum is pulled away from its equilibrium position by an angleof 8.55° and released from rest. Assume that friction can beneglected and that the resulting oscillatory motion is simpleharmonic motion.
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rad/s

(b) Using the position of the bob at its lowest point as thereference level, determine the total mechanical energy of thependulum as it swings back and forth.
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(c) What is the bob's speed as it passes through the lowest pointof the swing?
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