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14 Nov 2019

Light rays from the Sun, which is at an angle of 26° above thewesternhorizon, strike the still surface of a pond.

(a) What is the angle of incidence of theSun'srays on the pond?
°

(b) What is the angle of reflection of the rays that leave thepondsurface?
°

(c) In what direction and at what angle from the pond surfacearethe reflected rays traveling?
---Select---eastwardwestwardat ° above the pond surface
for part c i know direction iseastward butstill need the angle

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Casey Durgan
Casey DurganLv2
4 Mar 2019

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Related textbook solutions

Physics: Principles with Applications
7th Edition, 2013
Giancoli
ISBN: 9780321625922

Related questions

I'm working on this problem about two intersectingplanemirrors. I understand that the angle of incidence equalstheangle of reflection and that all the angles of a triangle add upto180, but I still cannot figuer this problem out. It is: Two planemirrors interesect at an angle of 50 degrees. Anincident light rayin a plane perpendicular to the two mirrorsmakes an angle of 70degrees with one mirror, reflects from it andthen from the other.What is the angle between the incidentand outgoing rays?
Any help on this would be amazing!!

You will be utiizing a basicoptic system.

The index of refraction of theplastic cylindrical lens depends on wavelength. Choose an anglewhich gives a good color separation and measure the index ofrefraction for blue and red light.

Question:How big is the difference in indices of refraction? How good is theapproximation that n is constant for thismaterial?

If this question doesnt make sense..then just answer ittheoretically speaking. That is how would we go about checkingwhether or not it conforms with the n as the constant for thematerial... Thanks!

Background info:

ThePhysics

The Law ofReflection

The law of reflection states that for a plane mirror, the angle ofincidence is equal to the angle of reflection, and that the tworays lie in a plane.

r

normal

. A light ray perpendicular to the surface has an angle ofincidence 0°.

The Law of Refraction –Snell’s Law

A ray of light passing from one substance (index ofrefraction

n1)into another (index of refraction n

2) across a plane boundary will be refracted. The angle the raymakes in one medium will be related to the angle in the secondmedium by the equation below, and that all rays lie in aplane.

(2)

Total InternalReflection

A ray incident on a medium with lower index of refraction willbe

totally internally reflected if sin θ1> n2/n1.There will be no transmitted beam for this incident angle. Ameasurement of the critical angle for total internalreflection can be used to determine the index of refraction of the substance.If n

2 = 1 (air), then the critical angle is:

sin θc = 1/

n

1. (3)

Polarization byReflection – Brewster’s Angle

If the angle between the reflected and refracted rays is 90°,then

tan θ

B = n2/n

1. (4)

At this angle, only light with polarization out of the plane ofreflection and refraction will be reflected. The reflected lightwill be completely polarized.

Figure3.

Refractionof Light Rays

Figure2.

Incidentand Reflected Rays

(1)

Always measure the angles with respect to the surface

A ray of "pink" light and a ray of green light are travelingparallel to one another as they strike an interface. The rays enterthe new material at a non zero angle.
Any part of the "pink" light taht is reflected by the interfacerebounds from the interface at an angle ( ) the incident angleis.

(a) less than
(b) equal to
(c) greater than

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