An infinite metal slab is located perpendicular to thex-axis, between x = 0 and x = 2.0 cm(see figure). The slab has a surface charge density of +4.8 ΓΒ 10-6C/m2 on each side.
(a) Find the magnitude of the potentialdifference between x = 0 and x = 8 cm.
|V(8 cm) - V(0)| =V
For parts (b) and (c), take the potential to be 0 at x= 0.
(b) What is the potential at x = 2.0 cm?.
V(2.0 cm) = V *
(c) What is the potential at x = 8 cm?.
V(8 cm) = V
HELP: The slab is made of aconducting material. Also, watch the signs: theelectric field always points in the direction of decreasingpotential.
For parts (d) and (e), take the potential to be 0 at x= -8 cm.
(d) What is the potential at x = 2.0 cm?.
V(2.0 cm) = V
(e) What is the potential at x = 10 cm?.
V(10 cm) = V
HELP: What is the direction of theelectric field to the left and to the right of the slab? How do theelectric field magnitudes in these regions compare?
