# Use Eq. (5) to calculate the resolution error in k, "Delta k", based on the resolution error in x=50 mm. when Delta x= 1mm and the resolution error in measuring m=50 g, is Delta m= 1 g. Use a value of k= 12000 dynes/cm.

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The telescopes on some commercial surveillance satellitescanresolve objects on the ground as small as 89 cm across (seeGoogleEarth), and the telescopes on military surveillancesatellitesreportedly can resolve objects as small as 14 cm across.Assumefirst that object resolution is determined entirely byRayleigh'scriterion and is not degraded by turbulence in theatmosphere. Alsoassume that the satellites are at a typicalaltitude of 394 km andthat the wavelength of visible light is 540nm. What would be therequired diameter of the telescope aperturefor**(a)** 89 cm resolutionand **(b)** 14cmresolution? **(c)** Now, considering thatturbulenceis certain to degrade resolution and that the aperturediameter ofthe Hubble Space Telescope is 2.4 m, what can you sayabout theanswer to**(b)**, i.e. is the militarysurveillanceresolution accomplished (1 depicts "yes", 0otherwise)?

(a) | Number | Units | This answer has no units Â° (degrees) m kg s m/s m/s^2 N J W N/mkgÂ·m/s or NÂ·s N/m^2 or Pa kg/m^3 g m/s^3 times |

(b) | Number | Units | This answer has no units Â° (degrees) m kg s m/s m/s^2 N J W N/mkgÂ·m/s or NÂ·s N/m^2 or Pa kg/m^3 g m/s^3 times |

(c) | Number | Units | This answer has no units Â° (degrees) m kg s m/s m/s^2 N J W N/mkgÂ·m/s or NÂ·s N/m^2 or Pa kg/m^3 g m/s^3 times |