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23 Nov 2019

A 3.0 kg block moving with a velocity of+3.8 m/s makes an elasticcollision with astationary block of mass 2.0 kg.

(a) Use conservation of momentum and thefactthat the relative speed of recession equals the relative speedofapproach to find the velocity of each block afterthecollision.
m/s (for the 3.0kg block)
m/s (for the 2.0kg block)

(b) Check your answer by calculating the initial and finalkineticenergies of each block.
J (initially for the 3.0 kg block)
J (initially for the 2.0 kg block)

J (finally for the 3.0 kg block)
J (finally for the 2.0 kg block)

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Related textbook solutions

Physics: Principles with Applications
7th Edition, 2013
Giancoli
ISBN: 9780321625922

Related questions

Can someone please help me with the following problem?

A 3.0 kg block is traveling in the -x direction at 5.0 m/s, anda1.0 kg block is traveling in the +x direction at 3.0 m/s.

a.) Find the velocity VCM of the center of mass.
b.) Subtract VCM from the velocity of each block tofindthe velocity of each block in the center-of-massreferenceframe.
c.) After they make a head-on elastic collision, the velocityofeach block is reversed (in the center-of-mass frame). Findthevelocity of each block in the center-of-mass frame afterthecollision.
d.) Transform back into the original frame by addingVCMto the velocity of each block.
e.) Check your result by finding the initial and finalkineticenergies of the blocks in the original frame andcomparingthem.

Thanks so much for your help!!! =)

I got part a and part e, but need help on b,c,d. Thanks somuch!

Problem 8-92a:
A 3.14-kg block is traveling in the -x direction at 5.48 m/s, and a1.15-kg block is traveling in the +x direction at 3.47 m/s.Calculate the velocity vcm of the center of mass.
-3.08 m/s
You are correct.

Problem 8-92b:
Subtract vcm from the velocity of each block to find the velocityof each block in the center-of-mass reference frame. Give velocityof the 3.14-kg block first, then the 1.15-kg block.

Incorrect.

Problem 8-92c:
After they make a head-on elastic collision, the velocity of eachblock is reversed (in the center-of-mass frame). Calculate thevelocity of each block in the center-of-mass frame after thecollision. Calculate the velocity for the 3.14-kg block first, thenthe 1.15-kg block.

Incorrect.

Problem 8-92d:
Transform back into the original frame by adding vcm to thevelocity of the 3.14-kg block, then do the same calculation for the1.15-kg block.


Problem 8-92e:
Check your result by calculating the initial and final kineticenergies of the blocks in the original frame. Enter the initialkinetic energy first.
5.41×101 J 5.41×101 J
You are correct.

Blocks A (mass 2.00 kg) and B (mass 10.00 kg, to the right of A) move on a frictionless, horizontal surface. Initially, block B is moving to the left at 0.500 m/s and block A is moving to the right at 2.00 m/s. The blocks are equipped with ideal spring bumpers. The collision is head on, so all motion before and after it is along a straight line. Find (a) the maximum energy stored in the spring bumpers and the velocity of each block at that time; (b) the velocity of each block after they have moved apart.

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