A playground merry-go-round ofradius R = 2.00 m has amoment ofinertia I = 245 kgÂ·m² and isrotatingat 9.0 rev/min about africtionless vertical axle. Facingthe axle, a 27.0 kg child hops onto the merry-go-round andmanagesto sit down on its edge. What is the new angular speed ofthemerry-go-round?

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Casey DurganLv2

30 Jun 2019

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A playground merry-go-round of radius 2.00 m hasamoment of inertia I = 295kgÂ·m² and is rotatingabout a frictionlessvertical axle. As a child of mass 25.0 kgstands at a distance of1.00 m from the axle, the system(merry-go-round and child) rotatesat the rate of 15.0 rev/min. Thechildthen proceeds to walk toward the edge of the merry-go-round.Whatis the angular speed of the system when the child reachestheedge?
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A playground merry-go-round has a radius of 4.20 {\rm m} and amoment of inertia of 255 kg m^2 and turns with negligible frictionabout a vertical axle through its center.

1)A child applies a 20.0 {\rm N} force tangentially to the edge ofthe merry-go-round for 22.0 {\rm s}. If the merry-go-round isinitially at rest, what is its angular velocity after this 22.0{\rm s} interval?

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A 3.0m diameter playground merry-go-round has a rotational inertia of 120 kg-m^2 and is spinning at 0.50 rev/s. What is the rotational kinetic energy of the merry-go-round? If four 25-kg children sit suddenly on the edge of the merry-go-round, what will be the new angular speed of the merry-go-round? With the children sitting on the edge of the merry-go-round what is the new angular kinetic energy of the merry-go-round? Was rotational kinetic energy "gained" or "lost" when the children jumped on the merry-go-round?

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A playground merry-go-round ofradius R = 2.00 m has amoment ofinertia I = 245 kgÂ·m² and isrotatingat 9.0 rev/min about africtionless vertical axle. Facingthe axle, a 27.0 kg child hops onto the merry-go-round andmanagesto sit down on its edge. What is the new angular speed ofthemerry-go-round?

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Physics: Principles with Applications

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A playground merry-go-round ofradius R = 2.00 m has amoment ofinertia I = 245 kgÂ·m2 and isrotatingat 9.0 rev/min about africtionless vertical axle. Facingthe axle, a 27.0 kg child hops onto the merry-go-round andmanagesto sit down on its edge. What is the new angular speed ofthemerry-go-round?

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Related textbook solutions

Physics: Principles with Applications

Related questions

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A playground merry-go-round ofradius R = 2.00 m has amoment ofinertia I = 245 kgÂ·m² and isrotatingat 9.0 rev/min about africtionless vertical axle. Facingthe axle, a 27.0 kg child hops onto the merry-go-round andmanagesto sit down on its edge. What is the new angular speed ofthemerry-go-round?