2
answers
0
watching
80
views
23 Nov 2019

A ball is launched with an initial velocity of 22.6 m/s at a 45°angle from the top of a cliffthat is 11.0 m above the water below.Useg = 10 m/s2 to simplify the calculations. Note:youcould answer these questions using projectile motion methods,buttry using an energy conservation approach instead.

(a) What is the ball’s speed when it hits the water?
1 m/s

(b) What is the ball’s speed when it reaches itsmaximumheight?
2 m/s

(c) What is the maximum height (measured from the water)reachedby the ball in its flight?
3 m

For unlimited access to Homework Help, a Homework+ subscription is required.

Unlock all answers

Get 1 free homework help answer.
Already have an account? Log in
Nestor Rutherford
Nestor RutherfordLv2
30 Jun 2019
Already have an account? Log in
Start filling in the gaps now
Log in