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23 Nov 2019

Hello,


I made this question, but got an incorrect answer (thetwosides of the divergence theorem gave different answers). Andwhen Iclick on the solution of the question I get an error. Couldyouplease send me the solution via e-mail? I don't need anymoreexplanation but the information supposed to be on the site.Mye-mail adress is [email protected]. Thank you.

Joran


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Related textbook solutions

Physics: Principles with Applications
7th Edition, 2013
Giancoli
ISBN: 9780321625922

Related questions

A mass m rests on a frictionless horizontal table and isconnected to rigid supports via 2 identical springs each of relaxedlength L0 and spring constantk. Each spring is stretched to a length L considerable greater thanL0. Horizontal displacementsof m from its equilibrium position are labeled x and y.
(Diagram insert didn't work, all it really tells you is that xis on the axis of the springs and y is perpendicular to thesprings)
a) Write down the differential equation of motion (i.e.,Newton's Law) governing small oscillations in the xdirection.
b) Same as a but in the y direction (assume that y <<L).
c) In terms of L and L0, calculate the ratio of the periods ofthe oscillations along x and y.
d) If at t=0 the mass m is released from the point x = y = A0with zero velocity, what are its x and y coordinates at any latertime t?
---------------------------
So, I started with just ma = -2kx for a, leading me to thedifferential equation x''(t) + (2k/m) x = 0.
Then I did basically the same thing with y.
However, when I get to c, there's my problem - I don't knowhow I could write any of this in L and L0.
Also, b doesn't really make sense to me because if y is smallwhen compared to L, it seems like there shouldn't be anyoscillation in the y direction.
The answer the back of the book shows for c and d are:
c) Tx/Ty = (1 - L0 / L)1/2
d) x(t) = A0cos( (2k/m)1/2 t)
y(t) = A0cos( (2k(L-L0)/mL)1/2 t)
I have no idea how they got to these answers. Can somebodyhelp me? It has something to do with springs already beingstretched, but it seems they are making an assumption somewherethat I don't understand.

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