I need the work and the answer so that I can apply the question andmake sure I'm doing it correctly.

You are travelling in your 2000 kg car at 11.7 m/s and wish toaccelerate to 26.1 m/s in 3.51 seconds, how much work, to thenearest joule, is required?

answers

watching

views

For unlimited access to Homework Help, a Homework+ subscription is required.

You have 0 free answers left.
Get unlimited access to 3.8 million step-by-step answers.

Get unlimited access

Already have an account? Log in

ijlalssck1940Lv2

11 Jul 2023

Unlock all answers

Get 1 free homework help answer.

Already have an account? Log in

You have 0 free answers left.
Get unlimited access to 3.8 million step-by-step answers.

Get unlimited access

Already have an account? Log in

Tod ThielLv2

19 Sep 2019

Already have an account? Log in

Related questions

A typical coal-fired power plant burns 320 metric tons of coalevery hour to generate 760 MW of electricity. 1 metric ton= 1000kg. The density of coal is 1500 kg/m^3 and its heat of combustionis 28 MJ/kg. Assume that all heat is transferred from the fuel tothe boiler and that all the work done in spinning the turbine istransformed into electrical energy.

What is the power plant's thermal efficiency?

What I know:
e= W/Qh
1 Watt = 1 Joule/sec

How I've tried to solve it:
320 metric tons * 1000 kg = 320000kg / 28 MJ/kg = 11428.6 MJ? I'mnot sure if I've done it to get the right units.
I know I need both the above number and the 760 MWatts to be inJoules per second.
When I divide the two resulting numbers I get 6.7% efficiency whichisn't correct. Can someone explain where I'm going wrong?

A 8 kg box with initial speed 8 m/s slides across a floor and comes to a stop after 1.8 seconds. What is the coefficient of kinetic friction? How far does the box move? You put a 3 kg block in the box, so the total mass is now 11kg, and you launch this heavier box with an initial speed of 8 m/s. How long does it take to stop? What formulas do I need to use and what steps do I take when approaching a question like this?

A sports car claims that it can start from rest and reach 60mph (26.8 m/s) in a distance of 33.5 meters. To reach its maximummspeed, it accelerates at this constant rate for 11.25seconds.

a) How many seconds does it take to reach 60 mph?
- I got 1.25 seconds

b) What is the maximum speed of this car?
- Using kinematics I got 120.6 m/s

c) If the mass is 1900 kg, what force must the car provide tokeep it traveling at this maximum speed ( Hint: don't forgetfriction)

- I know that Fnet= mass x acceleration, and that gives me1900 x 10.72 = 20,368 N

but this is not taking into account friction. What role doesfriction play and how can I calculate it properly?

d) I was driving this car at a maximum speed on a test trackwhen a deer ran out in front of me. My reaction time was 0.5seconds, before I hit the brakes. Assuming that the engine is nolonger applying any forward force, and my wheels lock up, how farwill I travel before I come to a stop after seeing the deer (giveanswer in miles, using: 1 Km = 0.62 miles)?

e) How much time will elapse from the time that I see the deeruntil I stop?