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23 Nov 2019

A spherically symmetric charge distribution produces the electricfield = (600/r) N/C, where r is in m.

(a) What is the electric field strength at r = 8 cm?
in N/C
(b) What is the electric flux through a 16 cm diameter sphericalsurface that is concentric with the charge distribution?
in N m2/C
(c) How much charge is inside this 16 cm diameter sphericalsurface?
in nC

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Related textbook solutions

Physics: Principles with Applications
7th Edition, 2013
Giancoli
ISBN: 9780321625922

Related questions

<p>a spherically symetric charge distribution produces theelectric field that increases as you move radially away from thecenter of the distribution until you are 10cm away from thecenter.<br /><br />If E= 6280 r<sup>2</sup>N/C in the radial direction for r measured inmeters:</p>
<p>what is the electric field strength at r = 31.4 cm?</p>
<p>what is the electric flux through a 31.4 -cm-diameterspherical surface that is concentric with the chargedistribution?</p>
<p>what is the total charge in this distribution?</p>

The electric field strength 2.0 cm from a 10 cm diameter metal ball is 50,000 N/C. What is the charge (in nC) on the ball?

Gauss' Law states that the electric flux through a closed"Gaussian" surface equals the net charge inside divided by theconstant
where C2/(N m2).
(a) Suppose that a charge -3.0 nC is located at the origin, andthat the Gaussian surface is a sphere of radius 15.0 cm centered onthe origin. What is the electric flux through the sphere?
N m2/C
(b) The Gaussian sphere is shifted so that its center is at x = 5.0cm. What is the flux now? N m2/C

(c) The Gaussian sphere is shifted so that its center is at x =35.0 cm. What is the flux now?
N m2/C
(d) A new Gaussian sphere is used of twice the original radiuscentered on the origin. What is the flux now?
N m2/C
(e) A new Gaussian surface is a tetrahedron centered on the originwith sides of length 15 cm. What is the flux now?
N m2/C

(f) A second charge +4.5 nC is added located at x = 17.0 cm. AGaussian sphere of radius 15.0 cm is centered on the origin. Whatis the flux through the sphere?
N m2/C

(g) The sphere in part (f) is now centered at x = 5.0 cm. What isthe flux through the sphere?
N m2/C

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