<DIV>Suppose in the figure that the four identical currents i = 6 A, into or out of the page as shown, form a square of side 118 cm. What is the force per unit length (magnitude and direction) on the wire in the bottom left hand corner? (N/m) Take the positive y direction as up and the positive x direction as to the right.<BR><BR>I do know all of the answers are supposed to be in N/m<BR><BR>http://loncapa2.physics.sc.edu/res/sc/gblanpied/courses/usclib/hrw8/hrwpictures/30-42.jpg<BR><BR>(a)What is the magnitude of the force per unit length?<BR><BR>(b)What is the x component of the force per unit length?<BR><BR>(c)What is the y component of the force per unit length?<BR><BR><BR><BR><BR>******** This method was previously submitted and the answers were found incorrect so im reposting. Thanx guys.<BR><BR>first find magnetic field.<BR>then use F=BiL<BR>B=uI/2piR<BR>u is 4piX10^-7<BR>I is current, 6am<BR>R is distance from between teh wire.<BR>u get 1.02X10^-6 from top left or bot right wire. And 7.19X10^-7 for the top right.<BR>then plug into equation<BR>L is 1 cuz it says unit length.<BR>So u get x-component=1.02X10^-6X6+7.19X10^-7X6XCos45=9.17X10^-6 N<BR>y-component=-1.02X10^-6X6+7.19X10^-7X6Xsin45=-3.07X10^-6 N<BR>Then u use pythragram theorem<BR>square root of Fx^2+Fy^2=ur magnitude.<BR>which is 1.02X10^-5N.<BR>the answer to b, and C is already above.<BR>b is Fx or ur x component.<BR>c is Fy or ur y component. </DIV>
<DIV>Suppose in the figure that the four identical currents i = 6 A, into or out of the page as shown, form a square of side 118 cm. What is the force per unit length (magnitude and direction) on the wire in the bottom left hand corner? (N/m) Take the positive y direction as up and the positive x direction as to the right.<BR><BR>I do know all of the answers are supposed to be in N/m<BR><BR>http://loncapa2.physics.sc.edu/res/sc/gblanpied/courses/usclib/hrw8/hrwpictures/30-42.jpg<BR><BR>(a)What is the magnitude of the force per unit length?<BR><BR>(b)What is the x component of the force per unit length?<BR><BR>(c)What is the y component of the force per unit length?<BR><BR><BR><BR><BR>******** This method was previously submitted and the answers were found incorrect so im reposting. Thanx guys.<BR><BR>first find magnetic field.<BR>then use F=BiL<BR>B=uI/2piR<BR>u is 4piX10^-7<BR>I is current, 6am<BR>R is distance from between teh wire.<BR>u get 1.02X10^-6 from top left or bot right wire. And 7.19X10^-7 for the top right.<BR>then plug into equation<BR>L is 1 cuz it says unit length.<BR>So u get x-component=1.02X10^-6X6+7.19X10^-7X6XCos45=9.17X10^-6 N<BR>y-component=-1.02X10^-6X6+7.19X10^-7X6Xsin45=-3.07X10^-6 N<BR>Then u use pythragram theorem<BR>square root of Fx^2+Fy^2=ur magnitude.<BR>which is 1.02X10^-5N.<BR>the answer to b, and C is already above.<BR>b is Fx or ur x component.<BR>c is Fy or ur y component. </DIV>
