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23 Nov 2019
A particle has a charge of +1.5 µC and moves from point A topoint B, a distance of 0.18 m. The particle experiences a constantelectric force, and its motion is along the line of action of theforce. The difference between the particle's electric potentialenergy at A and B is EPEA - EPEB = +5.50 10-4 J.
(a) Find the magnitude and direction of the electric force thatacts on the particle. magnitude 1 N
direction perpendicular to
(b) Find the magnitude and direction of the electric field that theparticle experiences. magnitude 3 N/C
direction along
A particle has a charge of +1.5 µC and moves from point A topoint B, a distance of 0.18 m. The particle experiences a constantelectric force, and its motion is along the line of action of theforce. The difference between the particle's electric potentialenergy at A and B is EPEA - EPEB = +5.50 10-4 J.
(a) Find the magnitude and direction of the electric force thatacts on the particle. magnitude 1 N
direction perpendicular to
(b) Find the magnitude and direction of the electric field that theparticle experiences. magnitude 3 N/C
direction along
Elin HesselLv2
4 Mar 2019
