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23 Nov 2019
<p>A small helium-neonlaser emits red visible light with apower of 2.60 mW in a beam that has a diameter of 2.90 mm.<br/><br />*I found the amplitude of the electric field ofthe light, E = 790 V/m<br />*I also found the amplitude ofthe magnetic field of the light, B = 2.63μT</p>
<p><br />Part C<br />What is the average energydensity associated with the electric field?<br /> u =        J/m^3</p>
<p> </p>
<p>Part D</p>
<p>What is the average energy density associated with themagnetic field?</p>
<p>u =          J/m^3</p>
<p> </p>
<p>A brief explanation and steps would be awesome,thanks!!</p>
<p>A small helium-neonlaser emits red visible light with apower of 2.60 mW in a beam that has a diameter of 2.90 mm.<br/><br />*I found the amplitude of the electric field ofthe light, E = 790 V/m<br />*I also found the amplitude ofthe magnetic field of the light, B = 2.63μT</p>
<p><br />Part C<br />What is the average energydensity associated with the electric field?<br /> u =        J/m^3</p>
<p> </p>
<p>Part D</p>
<p>What is the average energy density associated with themagnetic field?</p>
<p>u =          J/m^3</p>
<p> </p>
<p>A brief explanation and steps would be awesome,thanks!!</p>
Elin HesselLv2
3 Feb 2019
