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23 Nov 2019
At time t1 = 2.00 s, the acceleration of a particle in counterclockwise circular motion is (7.00 m/s2) ihat + (8.00 m/s2) jhat. It moves at constant speed. At time t2 = 5.00 s (3/4 of a revolution later), its acceleration is (8.00 m/s2) ihat + (-7.00 m/s2) jhat. What is the radius of the path taken by the particle?
At time t1 = 2.00 s, the acceleration of a particle in counterclockwise circular motion is (7.00 m/s2) ihat + (8.00 m/s2) jhat. It moves at constant speed. At time t2 = 5.00 s (3/4 of a revolution later), its acceleration is (8.00 m/s2) ihat + (-7.00 m/s2) jhat. What is the radius of the path taken by the particle?
